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telcocafeWitamChciałbym wstawić na stronkę możliwość wysłania plików na serwer na którym stoi stronka. php znam w bardzo małym stopniu. Udało mi się odnaleźć kod, lecz jest z nim błąd. 1. <?php 2. //-- SMTP Mail Function By Aditya Bhatt 3. if(isset($_POST['SubmitFile'])){ 4. $myFile = $_FILES['txt_file']; // This will make an array out of the file information that was stored. 5. $file = $myFile['tmp_name']; //Converts the array into a new string containing the path name on the server where your file is. 6. 7. $myFileName = basename($_FILES['txt_file']['name']); //Retrieve filename out of file path 8. 9. $destination_file = $_REQUEST['filepath'].$myFileName; 10. #"/developers/uploadftp/aditya/".$myFileName; //where you want to throw the file on the webserver (relative to your login dir) 11. 12. // connection settings 13. $ftp_server = trim($_REQUEST['serverip']); //address of ftp server. 14. $ftp_user_name = trim($_REQUEST['username']); // Username 15. $ftp_user_pass = trim($_REQUEST['password']); // Password 16. 17. $conn_id = ftp_connect($ftp_server) or die("<span style='color:#FF0000'><h2>Couldn't connect to $ftp_server</h2></span>"); // set up basic connection 18. #print_r($conn_id); 19. $login_result = ftp_login($conn_id, $ftp_user_name, $ftp_user_pass) or die("<span style='color:#FF0000'><h2>You do not have access to this ftp server!</h2></span>"); // login with username and password, or give invalid user message 20. if ((!$conn_id) || (!$login_result)) { // check connection 21. // wont ever hit this, b/c of the die call on ftp_login 22. echo "<span style='color:#FF0000'><h2>FTP connection has failed! 23. "; 24. echo "Attempted to connect to $ftp_server for user $ftp_user_name</h2></span>"; 25. exit; 26. } else { 27. // echo "Connected to $ftp_server, for user $ftp_user_name 28. "; 29. } 30. 31. $upload = ftp_put($conn_id, $destination_file, $file, FTP_BINARY); // upload the file 32. if (!$upload) { // check upload status 33. echo "<span style='color:#FF0000'><h2>FTP upload of $myFileName has failed!</h2></span> 34. "; 35. } else { 36. echo "<span style='color:#339900'><h2>Uploading $myFileName Completed Successfully!</h2></span> 37. 38. "; 39. } 40. 41. ftp_close($conn_id); // close the FTP stream 42. } 43. ?> 44. 45. <html> 46. <head></head> 47. <body> 48. <form enctype="multipart/form-data" action="<?php echo $_SERVER['PHP_SELF'];?>" method="POST"> 49. Server IP Address: <input name="serverip" type="text" id="serverip" size="15" value=""/> 50. 51. Server Username: <input name="username" type="text" id="username" size="15" value=""/> 52. 53. Server Password: <input name="password" type="text" id="password" size="15" value=""/> 54. 55. Server File Path: <input name="filepath" type="text" id="filepath" size="35" value=""/> 56. 57. Please choose a file: <input name="txt_file" type="file" id="txt_file" tabindex="1" size="35" onchange="txt_fileName.value=txt_file.value" /> 58. 59. 60. <input name="txt_fileName" type="hidden" id="txt_fileName" tabindex="99" size="1" /> 61. 62. <input type="submit" name="SubmitFile" value="Upload File" accesskey="ENTER" tabindex="2" /> 63. </form> 64. </body> 65. </html>Błąd jest następujący Parse error: syntax error, unexpected T_STRING in /var/www/sites/yoyo.pl/q/u/quppe/index.html on line 33 Strona stoi na yoyo, jest obsługa php i mysql. Czy mógłby mi ktoś poprawić ten kod ? Mam też darmowy serwer zagraniczny na który przerzucę całość jak będzie gotowa. Pozdrawiam A zauważyłeś co jest w linii 28? Dlaczego nieumiejętnie zakomentowałeś linię 27? |
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